(4x^2+2x-4)/(x-2)=9

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Solution for (4x^2+2x-4)/(x-2)=9 equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(4*x^2+2*x-4)/(x-2) = 9 // - 9

(4*x^2+2*x-4)/(x-2)-9 = 0

(4*x^2+2*x-4)/(x-2)+(-9*(x-2))/(x-2) = 0

4*x^2-9*(x-2)+2*x-4 = 0

4*x^2-7*x+14 = 0

4*x^2-7*x+14 = 0

4*x^2-7*x+14 = 0

DELTA = (-7)^2-(4*4*14)

DELTA = -175

DELTA < 0

1 = 0

1/(x-2) = 0

1/(x-2) = 0 // * x-2

1 = 0

x belongs to the empty set

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